Conservation of momentum in two dimension

Recore the collsion on the top of the equirement as shown.

     before

during

after 

Set the initial velocity as the +x-direction.

 Find the slopes (velocitise) of each part of the lines.

x-axis
   pix=M1*v 1i=0.622m/s*0.0668kg=0.044 Ns
   p1x=M1*v 1fx=0.451m/s*0.0668kg=0.03 Ns
   p2x=M2*v 2fx=0.593m/s*0.0198kg=0.012 Ns
   p1x+p2x=0.42 Ns Approximate to pix 0.044Ns

y-axis
   piy=0
   p1y=M1*v 1fy=-0.009m/s*0.0668kg=-4.2x10^-3 Ns
   p2y=M2*v 2fy=0.161m/s*0.0198kg=3.2*10^-3 Ns
   p1y+p2y=-1*10^-3 Ns approximate to zero.

conform the conservation of momentum in both x and y axis.

Data 2

The x axis initial momentum is 0.039kg*m/s which is approximat to final momentum 0.036kg*m/s.

The y axis initial momentun is 0. the final momentum is 0.001.

Those values can conform the conservation of momentum in both x and y axis.